Hardin Township, Pike County, Illinois

Hardin Township
Township

Location in Pike County

Pike County's location in Illinois
Country United States
State Illinois
County Pike
Established November 8, 1853
Area
 • Total 37.41 sq mi (96.9 km2)
 • Land 37.39 sq mi (96.8 km2)
 • Water 0.03 sq mi (0.08 km2)  0.08%
Population (2010)
 • Total 212
 • Density 5.7/sq mi (2.2/km2)
Time zone CST (UTC-6)
 • Summer (DST) CDT (UTC-5)

Hardin Township is located in Pike County, Illinois. As of the 2010 census, its population was 212 and it contained 105 housing units.[1]

Geography

According to the 2010 census, the township encompasses an area of 37.41 square miles (96.9 km2), of which 37.39 square miles (96.8 km2) (or 99.95%) is land and 0.03 square miles (0.078 km2) (or 0.08%) is water.[1]

References

  1. 1 2 "Population, Housing Units, Area, and Density: 2010 - County -- County Subdivision and Place -- 2010 Census Summary File 1". United States Census. Retrieved 2013-05-28.

Coordinates: 39°31′42″N 90°44′49″W / 39.52833°N 90.74694°W / 39.52833; -90.74694


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